FInd the last two digit of (56789)^{41}

The last two digits of the given number will be dependent on the last two digits of 56789, that is 89.

Observe the last two digits of the following computations:

It follws a pattern and it starts repeating after every power which is a multiple of 12.

We need to find the 41th power of 89.

Thus, the number will have last two digits same as that of

Thus, the last two digits of are 49

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